What are the solutions to the equation 2x^2-20+46=0 ?

The solutions to the equation 2x^2-20+46=0 are x=sqrt(13)i,x=-sqrt(13)i

Find the zeros of 2x^2-20+46=0

The zeros of 2x^2-20+46=0 are x=sqrt(13)i,x=-sqrt(13)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 20 + 46 = 0

x = 13 i, x = - 13 i

Solution steps

2 x^{2} - 20 + 46 = 0

Move

20

to the right side

2 x^{2} + 46 = 20

Move

46

to the right side

2 x^{2} = - 26

Divide both sides by

2

x^{2} = - 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 13, x = - - 13

- 13 = 13 i

- - 13 = - 13 i

x = 13 i, x = - 13 i

5 x^{2} - 2 = 38

6 x^{2} = 5 x - 1

(x + 1) (x - 1) = 2 (x + 5)

x, 6 z = 72 - x^{2} - y^{2}

- 2 x^{2} - 7 x - 6

What are the solutions to the equation 2x^2-20+46=0 ?
The solutions to the equation 2x^2-20+46=0 are x=sqrt(13)i,x=-sqrt(13)i
Find the zeros of 2x^2-20+46=0
The zeros of 2x^2-20+46=0 are x=sqrt(13)i,x=-sqrt(13)i