What are the solutions to the equation 50-(x^2)/2 =26+x ?

The solutions to the equation 50-(x^2)/2 =26+x are x=-8,x=6

Find the zeros of 50-(x^2)/2 =26+x

The zeros of 50-(x^2)/2 =26+x are x=-8,x=6

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50 - \frac{x ^{2}}{2} = 26 + x

x = - 8, x = 6

Solution steps

50 - \frac{x ^{2}}{2} = 26 + x

Multiply both sides by

2

100 - x^{2} = 52 + 2 x

Move

2 x

to the left side

100 - x^{2} - 2 x = 52

Move

52

to the left side

- x^{2} - 2 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 48}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 48 = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 14}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 14}{2 ( - 1 )} : - 8

x = \frac{- ( - 2 ) - 14}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 8, x = 6

x^{2} + 7 - 8 = 0

12 x^{2} = 60 x

y = 4 x - x^{2}, x

6 x - x^{2} = x

x^{2} + 3 x - 43 = - 3 x - 3

What are the solutions to the equation 50-(x^2)/2 =26+x ?
The solutions to the equation 50-(x^2)/2 =26+x are x=-8,x=6
Find the zeros of 50-(x^2)/2 =26+x
The zeros of 50-(x^2)/2 =26+x are x=-8,x=6