What are the solutions to the equation 24x^2+8x-10=0 ?

The solutions to the equation 24x^2+8x-10=0 are x= 1/2 ,x=-5/6

Find the zeros of 24x^2+8x-10=0

The zeros of 24x^2+8x-10=0 are x= 1/2 ,x=-5/6

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24 x^{2} + 8 x - 10 = 0

x = \frac{1}{2}, x = - \frac{5}{6}

Decimal Notation

x = 0.5, x = - 0.83333 \dots

Solution steps

24 x^{2} + 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 24 ( - 10 )}{2 \cdot 24}

8^{2} - 4 \cdot 24 (- 10) = 32

x_{1, 2} = \frac{- 8 \pm 32}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 8 + 32}{2 \cdot 24}, x_{2} = \frac{- 8 - 32}{2 \cdot 24}

x = \frac{- 8 + 32}{2 \cdot 24} : \frac{1}{2}

x = \frac{- 8 - 32}{2 \cdot 24} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{6}

\frac{1}{12500} + \frac{3 x}{125} + x^{2} = 0

x (x + 2) = 195

2 (x - 1) (2 x + 3) = 8 x - 5 x (2 - 2 x) - 10

(v + 5)^{2} = 5

3 x^{2} = - x + 10

What are the solutions to the equation 24x^2+8x-10=0 ?
The solutions to the equation 24x^2+8x-10=0 are x= 1/2 ,x=-5/6
Find the zeros of 24x^2+8x-10=0
The zeros of 24x^2+8x-10=0 are x= 1/2 ,x=-5/6