What are the solutions to the equation 3x^2+18x-21=0 ?

The solutions to the equation 3x^2+18x-21=0 are x=1,x=-7

Find the zeros of 3x^2+18x-21=0

The zeros of 3x^2+18x-21=0 are x=1,x=-7

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3 x^{2} + 18 x - 21 = 0

x = 1, x = - 7

Solution steps

3 x^{2} + 18 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 ( - 21 )}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 (- 21) = 24

x_{1, 2} = \frac{- 18 \pm 24}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 24}{2 \cdot 3}, x_{2} = \frac{- 18 - 24}{2 \cdot 3}

x = \frac{- 18 + 24}{2 \cdot 3} : 1

x = \frac{- 18 - 24}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

0 = - x^{2} - 2 x + 3

3 - y^{2} = y + 1

(x + 5) (x - 4) = 3 (x + 5)

x, y = - \frac{x ^{2}}{2} + \frac{5}{4} x

x, x^{2} + 2 x y = 3 y^{2}

What are the solutions to the equation 3x^2+18x-21=0 ?
The solutions to the equation 3x^2+18x-21=0 are x=1,x=-7
Find the zeros of 3x^2+18x-21=0
The zeros of 3x^2+18x-21=0 are x=1,x=-7