What are the solutions to the equation (k+12)^2=97 ?

The solutions to the equation (k+12)^2=97 are k=sqrt(97)-12,k=-sqrt(97)-12

Find the zeros of (k+12)^2=97

The zeros of (k+12)^2=97 are k=sqrt(97)-12,k=-sqrt(97)-12

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(k + 12)^{2} = 97

k = 97 - 12, k = - 97 - 12

Decimal

k = - 2.15114 \dots, k = - 21.84885 \dots

Solution steps

(k + 12)^{2} = 97

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 12 = 97 : k = 97 - 12

Solve

k + 12 = - 97 : k = - 97 - 12

The solutions to the quadratic equation are:

k = 97 - 12, k = - 97 - 12

5 x^{2} + 9 x - 4 = 3 x + 4

3 - 3 x^{2} = 8 x

400 - p^{2} = 60 p - 5

3 x^{2} - \frac{3 x - 2}{4} = \frac{2 - x}{3}

x, x^{2} + y^{2} = a x

What are the solutions to the equation (k+12)^2=97 ?
The solutions to the equation (k+12)^2=97 are k=sqrt(97)-12,k=-sqrt(97)-12
Find the zeros of (k+12)^2=97
The zeros of (k+12)^2=97 are k=sqrt(97)-12,k=-sqrt(97)-12