What are the solutions to the equation 2/3 x^2+15=23 ?

The solutions to the equation 2/3 x^2+15=23 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 2/3 x^2+15=23

The zeros of 2/3 x^2+15=23 are x=2sqrt(3),x=-2sqrt(3)

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\frac{2}{3} x^{2} + 15 = 23

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

\frac{2}{3} x^{2} + 15 = 23

Move

15

to the right side

\frac{2}{3} x^{2} = 8

Multiply both sides by

3

2 x^{2} = 24

Divide both sides by

2

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

L (v) = 2 v^{2} + 50 v + 10

2 x^{2} + 16 x - 24 = 0

t, f n (t) = 5 t - t^{2}

x^{2} + 18 x = 6 x - 35

(x + 3)^{2} = (x - 3)^{2} + (x - 6) (x + 6) + 63

What are the solutions to the equation 2/3 x^2+15=23 ?
The solutions to the equation 2/3 x^2+15=23 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 2/3 x^2+15=23
The zeros of 2/3 x^2+15=23 are x=2sqrt(3),x=-2sqrt(3)