What are the solutions to the equation -2x^2+5x+4=0 ?

The solutions to the equation -2x^2+5x+4=0 are x=-(-5+sqrt(57))/4 ,x=(5+sqrt(57))/4

Find the zeros of -2x^2+5x+4=0

The zeros of -2x^2+5x+4=0 are x=-(-5+sqrt(57))/4 ,x=(5+sqrt(57))/4

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- 2 x^{2} + 5 x + 4 = 0

x = - \frac{- 5 + 57}{4}, x = \frac{5 + 57}{4}

Decimal Notation

x = - 0.63745 \dots, x = 3.13745 \dots

Solution steps

- 2 x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 4 = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 ( - 2 )}, x_{2} = \frac{- 5 - 57}{2 ( - 2 )}

x = \frac{- 5 + 57}{2 ( - 2 )} : - \frac{- 5 + 57}{4}

x = \frac{- 5 - 57}{2 ( - 2 )} : \frac{5 + 57}{4}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 57}{4}, x = \frac{5 + 57}{4}

16 p^{2} - 24 p + 5 = 0

x, 16 x^{2} - m^{2} = 0

x^{2} + 6 x - 78 = 3 (x - 8)

w, - 32 a w - 15 a^{2} = - 7 w^{2}

x, x^{2} + k x - 2 k^{2} = 0

What are the solutions to the equation -2x^2+5x+4=0 ?
The solutions to the equation -2x^2+5x+4=0 are x=-(-5+sqrt(57))/4 ,x=(5+sqrt(57))/4
Find the zeros of -2x^2+5x+4=0
The zeros of -2x^2+5x+4=0 are x=-(-5+sqrt(57))/4 ,x=(5+sqrt(57))/4