What are the solutions to the equation (x+9)^2=12 ?

The solutions to the equation (x+9)^2=12 are x=2sqrt(3)-9,x=-2sqrt(3)-9

Find the zeros of (x+9)^2=12

The zeros of (x+9)^2=12 are x=2sqrt(3)-9,x=-2sqrt(3)-9

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(x + 9)^{2} = 12

x = 23 - 9, x = - 23 - 9

Decimal Notation

x = - 5.53589 \dots, x = - 12.46410 \dots

Solution steps

(x + 9)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 12 : x = 23 - 9

Solve

x + 9 = - 12 : x = - 23 - 9

The solutions to the quadratic equation are:

x = 23 - 9, x = - 23 - 9

x, x^{2} + 4 x - 2 a y + 2 (2 - a^{2}) = 0

3 x^{2} + 10 x + 12 = 4

7 x^{2} = 23 x

4 x^{2} + 16 x = 0

x^{2} + \frac{x}{2} - \frac{1}{2} = 0

What are the solutions to the equation (x+9)^2=12 ?
The solutions to the equation (x+9)^2=12 are x=2sqrt(3)-9,x=-2sqrt(3)-9
Find the zeros of (x+9)^2=12
The zeros of (x+9)^2=12 are x=2sqrt(3)-9,x=-2sqrt(3)-9