What are the solutions to the equation (z+7)^2=-19 ?

The solutions to the equation (z+7)^2=-19 are z=sqrt(19)i-7,z=-sqrt(19)i-7

Find the zeros of (z+7)^2=-19

The zeros of (z+7)^2=-19 are z=sqrt(19)i-7,z=-sqrt(19)i-7

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(z + 7)^{2} = - 19

z = 19 i - 7, z = - 19 i - 7

Solution steps

(z + 7)^{2} = - 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 7 = - 19 : z = 19 i - 7

Solve

z + 7 = - - 19 : z = - 19 i - 7

The solutions to the quadratic equation are:

z = 19 i - 7, z = - 19 i - 7

x + 6 - 2 x = x - 24

\frac{9 ^{- 3}}{9 ^{12}}

- 5 + 7 y = 8 y - 6

\frac{a}{2} - 2 = - 10

\frac{3}{x + 1} < \frac{2}{x + 2}

What are the solutions to the equation (z+7)^2=-19 ?
The solutions to the equation (z+7)^2=-19 are z=sqrt(19)i-7,z=-sqrt(19)i-7
Find the zeros of (z+7)^2=-19
The zeros of (z+7)^2=-19 are z=sqrt(19)i-7,z=-sqrt(19)i-7