What are the solutions to the equation 175=-0.01q^2+200 ?

The solutions to the equation 175=-0.01q^2+200 are q=50,q=-50

Find the zeros of 175=-0.01q^2+200

The zeros of 175=-0.01q^2+200 are q=50,q=-50

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175 = - 0.01 q^{2} + 200

q = 50, q = - 50

Solution steps

175 = - 0.01 q^{2} + 200

Switch sides

- 0.01 q^{2} + 200 = 175

Move

200

to the right side

- 0.01 q^{2} = - 25

Divide both sides by

- 0.01

q^{2} = 2500

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 2500, q = - 2500

2500 = 50

- 2500 = - 50

q = 50, q = - 50

4 = x (x + 3)

a = \frac{1}{2} π r^{2}

(5 x + n)^{2} - 4 = 0

e (7) = - x^{2} - 9 x

x^{2} = 1 7^{2} + 8^{2}

What are the solutions to the equation 175=-0.01q^2+200 ?
The solutions to the equation 175=-0.01q^2+200 are q=50,q=-50
Find the zeros of 175=-0.01q^2+200
The zeros of 175=-0.01q^2+200 are q=50,q=-50