What are the solutions to the equation x^2+7x+49/4 =0 ?

The solutions to the equation x^2+7x+49/4 =0 are x=-7/2

Find the zeros of x^2+7x+49/4 =0

The zeros of x^2+7x+49/4 =0 are x=-7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 7 x + \frac{49}{4} = 0

x = - \frac{7}{2}

Decimal Notation

x = - 3.5

Solution steps

x^{2} + 7 x + \frac{49}{4} = 0

Multiply both sides by

4

4 x^{2} + 28 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 49}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 49 = 0

x_{1, 2} = \frac{- 28 \pm 0}{2 \cdot 4}

x = \frac{- 28}{2 \cdot 4}

\frac{- 28}{2 \cdot 4} = - \frac{7}{2}

x = - \frac{7}{2}

The solution to the quadratic equation is:

x = - \frac{7}{2}

- x^{2} - 10 x - 25 = 0

- 3 x^{2} - 7 = - 7

x^{2} - 2 x - 2 + 8 = 0

4 m^{2} - m - 3 = - m^{2}

20 x^{2} - x = 30

What are the solutions to the equation x^2+7x+49/4 =0 ?
The solutions to the equation x^2+7x+49/4 =0 are x=-7/2
Find the zeros of x^2+7x+49/4 =0
The zeros of x^2+7x+49/4 =0 are x=-7/2