What are the solutions to the equation 6x^2-5x=-4x+2 ?

The solutions to the equation 6x^2-5x=-4x+2 are x= 2/3 ,x=-1/2

Find the zeros of 6x^2-5x=-4x+2

The zeros of 6x^2-5x=-4x+2 are x= 2/3 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} - 5 x = - 4 x + 2

x = \frac{2}{3}, x = - \frac{1}{2}

Decimal Notation

x = 0.66666 \dots, x = - 0.5

Solution steps

6 x^{2} - 5 x = - 4 x + 2

Move

2

to the left side

6 x^{2} - 5 x - 2 = - 4 x

Move

4 x

to the left side

6 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 2) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 6}

x = \frac{- ( - 1 ) + 7}{2 \cdot 6} : \frac{2}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{2}

x^{2} - x - 30 = - 2 x

(x + 5)^{2} + 2 (3 x - 5) = 10

- x^{2} + \frac{1}{2} x = \frac{1}{2}

\frac{2 x ^{2} - 8}{5} - \frac{3 x - 9}{10} = x - 1

- x^{2} + 1 = 1

What are the solutions to the equation 6x^2-5x=-4x+2 ?
The solutions to the equation 6x^2-5x=-4x+2 are x= 2/3 ,x=-1/2
Find the zeros of 6x^2-5x=-4x+2
The zeros of 6x^2-5x=-4x+2 are x= 2/3 ,x=-1/2