What are the solutions to the equation -10t^2-12t=9982 ?

The solutions to the equation -10t^2-12t=9982 are t=-3/5-i(sqrt(24946))/5 ,t=-3/5+i(sqrt(24946))/5

Find the zeros of -10t^2-12t=9982

The zeros of -10t^2-12t=9982 are t=-3/5-i(sqrt(24946))/5 ,t=-3/5+i(sqrt(24946))/5

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- 10 t^{2} - 12 t = 9982

t = - \frac{3}{5} - i \frac{24946}{5}, t = - \frac{3}{5} + i \frac{24946}{5}

Solution steps

- 10 t^{2} - 12 t = 9982

Move

9982

to the left side

- 10 t^{2} - 12 t - 9982 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 10 ) ( - 9982 )}{2 ( - 10 )}

Simplify

(- 12)^{2} - 4 (- 10) (- 9982) : 424946 i

t_{1, 2} = \frac{- ( - 12 ) \pm 4 24946 i}{2 ( - 10 )}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 4 24946 i}{2 ( - 10 )}, t_{2} = \frac{- ( - 12 ) - 4 24946 i}{2 ( - 10 )}

t = \frac{- ( - 12 ) + 4 24946 i}{2 ( - 10 )} : - \frac{3}{5} - i \frac{24946}{5}

t = \frac{- ( - 12 ) - 4 24946 i}{2 ( - 10 )} : - \frac{3}{5} + i \frac{24946}{5}

The solutions to the quadratic equation are:

t = - \frac{3}{5} - i \frac{24946}{5}, t = - \frac{3}{5} + i \frac{24946}{5}

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What are the solutions to the equation -10t^2-12t=9982 ?
The solutions to the equation -10t^2-12t=9982 are t=-3/5-i(sqrt(24946))/5 ,t=-3/5+i(sqrt(24946))/5
Find the zeros of -10t^2-12t=9982
The zeros of -10t^2-12t=9982 are t=-3/5-i(sqrt(24946))/5 ,t=-3/5+i(sqrt(24946))/5