What are the solutions to the equation solvefor x,x^2=y^2+4z^2 ?

The solutions to the equation solvefor x,x^2=y^2+4z^2 are x=sqrt(y^2+4z^2),x=-sqrt(y^2+4z^2)

Find the zeros of solvefor x,x^2=y^2+4z^2

The zeros of solvefor x,x^2=y^2+4z^2 are x=sqrt(y^2+4z^2),x=-sqrt(y^2+4z^2)

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solve for

x, x^{2} = y^{2} + 4 z^{2}

x = y^{2} + 4 z^{2}, x = - y^{2} + 4 z^{2}

Solution steps

x^{2} = y^{2} + 4 z^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y^{2} + 4 z^{2}, x = - y^{2} + 4 z^{2}

2 x^{2} + 12 x = - 3

8 x^{2} + 13 x - 6 = 0

x, y = x^{2} - 4 x

(x - 7)^{2} = 15

j (x) = - 2 x^{2} + 8 x - 9

What are the solutions to the equation solvefor x,x^2=y^2+4z^2 ?
The solutions to the equation solvefor x,x^2=y^2+4z^2 are x=sqrt(y^2+4z^2),x=-sqrt(y^2+4z^2)
Find the zeros of solvefor x,x^2=y^2+4z^2
The zeros of solvefor x,x^2=y^2+4z^2 are x=sqrt(y^2+4z^2),x=-sqrt(y^2+4z^2)