What are the solutions to the equation 9k^2-18k+5=0 ?

The solutions to the equation 9k^2-18k+5=0 are k= 5/3 ,k= 1/3

Find the zeros of 9k^2-18k+5=0

The zeros of 9k^2-18k+5=0 are k= 5/3 ,k= 1/3

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9 k^{2} - 18 k + 5 = 0

k = \frac{5}{3}, k = \frac{1}{3}

Decimal

k = 1.66666 \dots, k = 0.33333 \dots

Solution steps

9 k^{2} - 18 k + 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 5 = 12

k_{1, 2} = \frac{- ( - 18 ) \pm 12}{2 \cdot 9}

Separate the solutions

k_{1} = \frac{- ( - 18 ) + 12}{2 \cdot 9}, k_{2} = \frac{- ( - 18 ) - 12}{2 \cdot 9}

k = \frac{- ( - 18 ) + 12}{2 \cdot 9} : \frac{5}{3}

k = \frac{- ( - 18 ) - 12}{2 \cdot 9} : \frac{1}{3}

The solutions to the quadratic equation are:

k = \frac{5}{3}, k = \frac{1}{3}

x, m x^{2} - m x + 3 = 0

\frac{2}{3} x^{2} = 6

4 x^{2} - 16 x - (- 20) = 0

x^{2} - 16 x + 61 = 0

(2 x + 1)^{2} = x^{2} + 1

What are the solutions to the equation 9k^2-18k+5=0 ?
The solutions to the equation 9k^2-18k+5=0 are k= 5/3 ,k= 1/3
Find the zeros of 9k^2-18k+5=0
The zeros of 9k^2-18k+5=0 are k= 5/3 ,k= 1/3