What are the solutions to the equation 0=-15*t^2+20*t ?

The solutions to the equation 0=-15*t^2+20*t are t=0,t= 4/3

Find the zeros of 0=-15*t^2+20*t

The zeros of 0=-15*t^2+20*t are t=0,t= 4/3

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0 = - 15 \cdot t^{2} + 20 \cdot t

t = 0, t = \frac{4}{3}

Decimal Notation

t = 0, t = 1.33333 \dots

Solution steps

0 = - 15 t^{2} + 20 t

Switch sides

- 15 t^{2} + 20 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 15 ) \cdot 0}{2 ( - 15 )}

2 0^{2} - 4 (- 15) \cdot 0 = 20

t_{1, 2} = \frac{- 20 \pm 20}{2 ( - 15 )}

Separate the solutions

t_{1} = \frac{- 20 + 20}{2 ( - 15 )}, t_{2} = \frac{- 20 - 20}{2 ( - 15 )}

t = \frac{- 20 + 20}{2 ( - 15 )} : 0

t = \frac{- 20 - 20}{2 ( - 15 )} : \frac{4}{3}

The solutions to the quadratic equation are:

t = 0, t = \frac{4}{3}

a^{2} - 4 ab + 4 b^{2}

(x + 4)^{2} - 96 = 0

\frac{5}{3} y - (\frac{5}{6} + \frac{2}{3} y) = 0

- 6 < x + 5

\frac{3}{10} + \frac{1}{10}

What are the solutions to the equation 0=-15*t^2+20*t ?
The solutions to the equation 0=-15*t^2+20*t are t=0,t= 4/3
Find the zeros of 0=-15*t^2+20*t
The zeros of 0=-15*t^2+20*t are t=0,t= 4/3