What are the solutions to the equation 3x^2+2x-e=0 ?

The solutions to the equation 3x^2+2x-e=0 are x=(-2+sqrt(4+12e))/6 ,x=(-2-sqrt(4+12e))/6

Find the zeros of 3x^2+2x-e=0

The zeros of 3x^2+2x-e=0 are x=(-2+sqrt(4+12e))/6 ,x=(-2-sqrt(4+12e))/6

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3 x^{2} + 2 x - e = 0

x = \frac{- 2 + 4 + 12 e}{6}, x = \frac{- 2 - 4 + 12 e}{6}

Decimal Notation

x = 0.67523 \dots, x = - 1.34189 \dots

Solution steps

3 x^{2} + 2 x - e = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - e )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- e) = 4 + 12 e

x_{1, 2} = \frac{- 2 \pm 4 + 12 e}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4 + 12 e}{2 \cdot 3}, x_{2} = \frac{- 2 - 4 + 12 e}{2 \cdot 3}

x = \frac{- 2 + 4 + 12 e}{2 \cdot 3} : \frac{- 2 + 4 + 12 e}{6}

x = \frac{- 2 - 4 + 12 e}{2 \cdot 3} : \frac{- 2 - 4 + 12 e}{6}

The solutions to the quadratic equation are:

x = \frac{- 2 + 4 + 12 e}{6}, x = \frac{- 2 - 4 + 12 e}{6}

3 x^{2} + 9 x + 2 = 4

10 b^{2} - 15 b = 8 b - 12

x^{2} - 2 x + 6 = 2 x^{2} - 6 x - 26

10 x^{2} + (20 k + 50) x + 10 k = 0

x^{2} - x - 6 = 69

What are the solutions to the equation 3x^2+2x-e=0 ?
The solutions to the equation 3x^2+2x-e=0 are x=(-2+sqrt(4+12e))/6 ,x=(-2-sqrt(4+12e))/6
Find the zeros of 3x^2+2x-e=0
The zeros of 3x^2+2x-e=0 are x=(-2+sqrt(4+12e))/6 ,x=(-2-sqrt(4+12e))/6