What are the solutions to the equation 9x^2+12x+5=10 ?

The solutions to the equation 9x^2+12x+5=10 are x= 1/3 ,x=-5/3

Find the zeros of 9x^2+12x+5=10

The zeros of 9x^2+12x+5=10 are x= 1/3 ,x=-5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 12 x + 5 = 10

x = \frac{1}{3}, x = - \frac{5}{3}

Decimal Notation

x = 0.33333 \dots, x = - 1.66666 \dots

Solution steps

9 x^{2} + 12 x + 5 = 10

Move

10

to the left side

9 x^{2} + 12 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 (- 5) = 18

x_{1, 2} = \frac{- 12 \pm 18}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 18}{2 \cdot 9}, x_{2} = \frac{- 12 - 18}{2 \cdot 9}

x = \frac{- 12 + 18}{2 \cdot 9} : \frac{1}{3}

x = \frac{- 12 - 18}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{5}{3}

v, p^{1} v^{1} = p^{2} v^{2}

3 x^{2} - 5 x = 0

x, x^{2} - 3 m x + 8 = 0

(x + \frac{1}{2})^{2} = \frac{16}{9}

x, (x - 1) (3 x + 2 y - 1) = c

What are the solutions to the equation 9x^2+12x+5=10 ?
The solutions to the equation 9x^2+12x+5=10 are x= 1/3 ,x=-5/3
Find the zeros of 9x^2+12x+5=10
The zeros of 9x^2+12x+5=10 are x= 1/3 ,x=-5/3