What are the solutions to the equation x^2+16x+88=0 ?

The solutions to the equation x^2+16x+88=0 are x=-8+2sqrt(6)i,x=-8-2sqrt(6)i

Find the zeros of x^2+16x+88=0

The zeros of x^2+16x+88=0 are x=-8+2sqrt(6)i,x=-8-2sqrt(6)i

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x^{2} + 16 x + 88 = 0

x = - 8 + 26 i, x = - 8 - 26 i

Solution steps

x^{2} + 16 x + 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 88}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 88 : 46 i

x_{1, 2} = \frac{- 16 \pm 4 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 4 6 i}{2 \cdot 1}, x_{2} = \frac{- 16 - 4 6 i}{2 \cdot 1}

x = \frac{- 16 + 4 6 i}{2 \cdot 1} : - 8 + 26 i

x = \frac{- 16 - 4 6 i}{2 \cdot 1} : - 8 - 26 i

The solutions to the quadratic equation are:

x = - 8 + 26 i, x = - 8 - 26 i

(2 x + 3)^{2} = 117 - x^{2}

2 x^{2} + (x - 15)^{2} = 4 x + 185

x^{2} + 24 x + 140 = 0

15 x^{2} + 12 = - 8 x

x^{2} - 3 x = 12 - 3 (x - 2)

What are the solutions to the equation x^2+16x+88=0 ?
The solutions to the equation x^2+16x+88=0 are x=-8+2sqrt(6)i,x=-8-2sqrt(6)i
Find the zeros of x^2+16x+88=0
The zeros of x^2+16x+88=0 are x=-8+2sqrt(6)i,x=-8-2sqrt(6)i