What are the solutions to the equation x^2-10x+25=2 ?

The solutions to the equation x^2-10x+25=2 are x=5+sqrt(2),x=5-sqrt(2)

Find the zeros of x^2-10x+25=2

The zeros of x^2-10x+25=2 are x=5+sqrt(2),x=5-sqrt(2)

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x^{2} - 10 x + 25 = 2

x = 5 + 2, x = 5 - 2

Decimal Notation

x = 6.41421 \dots, x = 3.58578 \dots

Solution steps

x^{2} - 10 x + 25 = 2

Move

2

to the left side

x^{2} - 10 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 23 = 22

x_{1, 2} = \frac{- ( - 10 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 2}{2 \cdot 1} : 5 + 2

x = \frac{- ( - 10 ) - 2 2}{2 \cdot 1} : 5 - 2

The solutions to the quadratic equation are:

x = 5 + 2, x = 5 - 2

6 x^{2} - 29 x - 5 = 0

\frac{x}{2} x = 3

3 x^{2} - 27 x - 30 = 0

x^{2} - 6 x - 5 = 0

x^{2} + 4 x + 31 = 0

What are the solutions to the equation x^2-10x+25=2 ?
The solutions to the equation x^2-10x+25=2 are x=5+sqrt(2),x=5-sqrt(2)
Find the zeros of x^2-10x+25=2
The zeros of x^2-10x+25=2 are x=5+sqrt(2),x=5-sqrt(2)