What are the solutions to the equation solvefor y,a^2y^2+3aby+2b^2=0 ?

The solutions to the equation solvefor y,a^2y^2+3aby+2b^2=0 are y=-b/a ,y=-(2b)/a ;\quad a\ne 0

Find the zeros of solvefor y,a^2y^2+3aby+2b^2=0

The zeros of solvefor y,a^2y^2+3aby+2b^2=0 are y=-b/a ,y=-(2b)/a ;\quad a\ne 0

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y, a^{2} y^{2} + 3 ab y + 2 b^{2} = 0

y = - \frac{b}{a}, y = - \frac{2 b}{a}; a \neq = 0

Solution steps

a^{2} y^{2} + 3 ab y + 2 b^{2} = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 ab \pm ( 3 ab ) ^{2} - 4 a ^{2} \cdot 2 b ^{2}}{2 a ^{2}}

Simplify

(3 ab)^{2} - 4 a^{2} \cdot 2 b^{2} : ab

y_{1, 2} = \frac{- 3 ab \pm ab}{2 a ^{2}}; a \neq = 0

Separate the solutions

y_{1} = \frac{- 3 ab + ab}{2 a ^{2}}, y_{2} = \frac{- 3 ab - ab}{2 a ^{2}}

y = \frac{- 3 ab + ab}{2 a ^{2}} : - \frac{b}{a}

y = \frac{- 3 ab - ab}{2 a ^{2}} : - \frac{2 b}{a}

The solutions to the quadratic equation are:

y = - \frac{b}{a}, y = - \frac{2 b}{a}; a \neq = 0

2 x^{2} - 2 x - 2 = x

- x^{2} + 862 = 0

x^{2} + x - 12 = 1

(x - 5) (x + 2) = 18

(x - 13)^{2} = (x - 12)^{2} + (x - 5)^{2}

What are the solutions to the equation solvefor y,a^2y^2+3aby+2b^2=0 ?
The solutions to the equation solvefor y,a^2y^2+3aby+2b^2=0 are y=-b/a ,y=-(2b)/a ;\quad a\ne 0
Find the zeros of solvefor y,a^2y^2+3aby+2b^2=0
The zeros of solvefor y,a^2y^2+3aby+2b^2=0 are y=-b/a ,y=-(2b)/a ;\quad a\ne 0