What are the solutions to the equation 0=x^2+1 2/3 x-2/3 ?

The solutions to the equation 0=x^2+1 2/3 x-2/3 are x= 1/3 ,x=-2

Find the zeros of 0=x^2+1 2/3 x-2/3

The zeros of 0=x^2+1 2/3 x-2/3 are x= 1/3 ,x=-2

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0 = x^{2} + 1 \frac{2}{3} x - \frac{2}{3}

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

0 = x^{2} + 1 \frac{2}{3} x - \frac{2}{3}

Convert mixed numbers to improper fractions:

1 \frac{2}{3} = \frac{5}{3}

0 = x^{2} + \frac{5}{3} x - \frac{2}{3}

Multiply both sides by

3

0 = 3 x^{2} + 5 x - 2

Switch sides

3 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 2) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 3}, x_{2} = \frac{- 5 - 7}{2 \cdot 3}

x = \frac{- 5 + 7}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 5 - 7}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

5 v^{2} - 7 v + 4 = 6

4 (x - 2)^{2} = (x - 8)^{2}

(- x - 1) (x + 10) + 12 = 0

2 x^{2} + 14 x - 60 = 0

3 s^{2} + 4 s - 4 = 0

What are the solutions to the equation 0=x^2+1 2/3 x-2/3 ?
The solutions to the equation 0=x^2+1 2/3 x-2/3 are x= 1/3 ,x=-2
Find the zeros of 0=x^2+1 2/3 x-2/3
The zeros of 0=x^2+1 2/3 x-2/3 are x= 1/3 ,x=-2