What are the solutions to the equation y^2-14y=-26 ?

The solutions to the equation y^2-14y=-26 are y=7+sqrt(23),y=7-sqrt(23)

Find the zeros of y^2-14y=-26

The zeros of y^2-14y=-26 are y=7+sqrt(23),y=7-sqrt(23)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 14 y = - 26

y = 7 + 23, y = 7 - 23

Decimal

y = 11.79583 \dots, y = 2.20416 \dots

Solution steps

y^{2} - 14 y = - 26

Move

26

to the left side

y^{2} - 14 y + 26 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 26 = 223

y_{1, 2} = \frac{- ( - 14 ) \pm 2 23}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 23}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 23}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 23}{2 \cdot 1} : 7 + 23

y = \frac{- ( - 14 ) - 2 23}{2 \cdot 1} : 7 - 23

The solutions to the quadratic equation are:

y = 7 + 23, y = 7 - 23

x, x^{2} + 4 x + y^{2} - 6 y + z = - 8

c^{2} = 7^{2} + 2 4^{2}

28.78712 = \frac{3}{4} x^{2}

3 t^{2} + 4 t - 4 = 0

(x - 3) (x + 1) = 5

What are the solutions to the equation y^2-14y=-26 ?
The solutions to the equation y^2-14y=-26 are y=7+sqrt(23),y=7-sqrt(23)
Find the zeros of y^2-14y=-26
The zeros of y^2-14y=-26 are y=7+sqrt(23),y=7-sqrt(23)