What are the solutions to the equation (x+5)(x-2)=-12 ?

The solutions to the equation (x+5)(x-2)=-12 are x=-1,x=-2

Find the zeros of (x+5)(x-2)=-12

The zeros of (x+5)(x-2)=-12 are x=-1,x=-2

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(x + 5) (x - 2) = - 12

x = - 1, x = - 2

Solution steps

(x + 5) (x - 2) = - 12

Expand

(x + 5) (x - 2) : x^{2} + 3 x - 10

x^{2} + 3 x - 10 = - 12

Move

12

to the left side

x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 1}, x_{2} = \frac{- 3 - 1}{2 \cdot 1}

x = \frac{- 3 + 1}{2 \cdot 1} : - 1

x = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

12 + 0.3 q = 111 - 0.1 q^{2}

x, 3 x^{2} y = x + 9

x, y = 9 - x^{2}

v, p = \frac{v ^{2}}{r}

a^{2} - 4 a - 21 = 0

What are the solutions to the equation (x+5)(x-2)=-12 ?
The solutions to the equation (x+5)(x-2)=-12 are x=-1,x=-2
Find the zeros of (x+5)(x-2)=-12
The zeros of (x+5)(x-2)=-12 are x=-1,x=-2