What are the solutions to the equation completesquare 2x^2-8x+8=0 ?

The solutions to the equation completesquare 2x^2-8x+8=0 are x=2

Find the zeros of completesquare 2x^2-8x+8=0

The zeros of completesquare 2x^2-8x+8=0 are x=2

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2 x^{2} - 8 x + 8 = 0

x = 2

Solution steps

2 x^{2} - 8 x + 8 = 0

Move

8

to the right side

2 x^{2} - 8 x = - 8

Divide both sides by

2

\frac{2 x ^{2} - 8 x}{2} = \frac{- 8}{2}

x^{2} - 4 x = - 4

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 0

Solve

x - 2 = 0 : x = 2

The solution to the quadratic equation is:

x = 2

15 x^{2} - 38 x - 32 = 0

3 x^{2} - 4 x + 10 = 0

x^{2} + 101.9 x + 2 \cdot 1 0^{5} = 0

2 x^{2} - 8 x + 3 = 0

x^{2} + 4 x + \frac{76}{3} = 0

What are the solutions to the equation completesquare 2x^2-8x+8=0 ?
The solutions to the equation completesquare 2x^2-8x+8=0 are x=2
Find the zeros of completesquare 2x^2-8x+8=0
The zeros of completesquare 2x^2-8x+8=0 are x=2