What are the solutions to the equation solvefor a,a^2-2a=b^2-2b ?

The solutions to the equation solvefor a,a^2-2a=b^2-2b are a=b,a=-b+2

Find the zeros of solvefor a,a^2-2a=b^2-2b

The zeros of solvefor a,a^2-2a=b^2-2b are a=b,a=-b+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

a, a^{2} - 2 a = b^{2} - 2 b

a = b, a = - b + 2

Solution steps

a^{2} - 2 a = b^{2} - 2 b

Move

2 b

to the left side

a^{2} - 2 a + 2 b = b^{2}

Move

b^{2}

to the left side

a^{2} - 2 a + 2 b - b^{2} = 0

Factor

a^{2} - 2 a + 2 b - b^{2} : (a - b) (a + b - 2)

(a - b) (a + b - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - b = 0 or a + b - 2 = 0

Solve

a - b = 0 : a = b

Solve

a + b - 2 = 0 : a = - b + 2

The solutions to the quadratic equation are:

a = b, a = - b + 2

- x^{2} + (k - 1) x + 4 = 0

x^{2} + 5 x + 5 + 8 = 0

x, x^{2} + 5 x = 0

4 x - x^{2} - 3 = 0

5 x^{2} - 7 x - 1 = 0

What are the solutions to the equation solvefor a,a^2-2a=b^2-2b ?
The solutions to the equation solvefor a,a^2-2a=b^2-2b are a=b,a=-b+2
Find the zeros of solvefor a,a^2-2a=b^2-2b
The zeros of solvefor a,a^2-2a=b^2-2b are a=b,a=-b+2