What are the solutions to the equation 3y^2-10y+11=4 ?

The solutions to the equation 3y^2-10y+11=4 are y= 7/3 ,y=1

Find the zeros of 3y^2-10y+11=4

The zeros of 3y^2-10y+11=4 are y= 7/3 ,y=1

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3 y^{2} - 10 y + 11 = 4

y = \frac{7}{3}, y = 1

Decimal Notation

y = 2.33333 \dots, y = 1

Solution steps

3 y^{2} - 10 y + 11 = 4

Move

4

to the left side

3 y^{2} - 10 y + 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 7 = 4

y_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 3}, y_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 3}

y = \frac{- ( - 10 ) + 4}{2 \cdot 3} : \frac{7}{3}

y = \frac{- ( - 10 ) - 4}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

y = \frac{7}{3}, y = 1

x^{2} + 43 x + 450 = 0

0.72 - 0.5 r^{2} = 0

2 x^{2} + 10 = 5 x + 7

x^{2} - 2 x + 3 = 3 - 2 x

100 = 500 - 4 q^{2}

What are the solutions to the equation 3y^2-10y+11=4 ?
The solutions to the equation 3y^2-10y+11=4 are y= 7/3 ,y=1
Find the zeros of 3y^2-10y+11=4
The zeros of 3y^2-10y+11=4 are y= 7/3 ,y=1