What are the solutions to the equation 4(2x-1)^2=8 ?

The solutions to the equation 4(2x-1)^2=8 are x=(sqrt(2)+1)/2 ,x=(-sqrt(2)+1)/2

Find the zeros of 4(2x-1)^2=8

The zeros of 4(2x-1)^2=8 are x=(sqrt(2)+1)/2 ,x=(-sqrt(2)+1)/2

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4 (2 x - 1)^{2} = 8

x = \frac{2 + 1}{2}, x = \frac{- 2 + 1}{2}

Decimal Notation

x = 1.20710 \dots, x = - 0.20710 \dots

Solution steps

4 (2 x - 1)^{2} = 8

Divide both sides by

4

(2 x - 1)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 2 : x = \frac{2 + 1}{2}

Solve

2 x - 1 = - 2 : x = \frac{- 2 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 1}{2}, x = \frac{- 2 + 1}{2}

(x) = - 10 x^{2} - 2500 x + 1000000

4 v^{2} - 15 v + 5 = - 3 v

x, x^{2} - 4 x y + 3 x + 25 y - 6 = 0

2 x^{2} + 13 x + 12 = (2 x + 3)^{2}

x^{2} + \frac{90 x}{2000} + \frac{1500}{2000} = 0

What are the solutions to the equation 4(2x-1)^2=8 ?
The solutions to the equation 4(2x-1)^2=8 are x=(sqrt(2)+1)/2 ,x=(-sqrt(2)+1)/2
Find the zeros of 4(2x-1)^2=8
The zeros of 4(2x-1)^2=8 are x=(sqrt(2)+1)/2 ,x=(-sqrt(2)+1)/2