What are the solutions to the equation -x^2+4x=6 ?

The solutions to the equation -x^2+4x=6 are x=2-sqrt(2)i,x=2+sqrt(2)i

Find the zeros of -x^2+4x=6

The zeros of -x^2+4x=6 are x=2-sqrt(2)i,x=2+sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 4 x = 6

x = 2 - 2 i, x = 2 + 2 i

Solution steps

- x^{2} + 4 x = 6

Move

6

to the left side

- x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 6) : 22 i

x_{1, 2} = \frac{- 4 \pm 2 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 2 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 2 i}{2 ( - 1 )}

x = \frac{- 4 + 2 2 i}{2 ( - 1 )} : 2 - 2 i

x = \frac{- 4 - 2 2 i}{2 ( - 1 )} : 2 + 2 i

The solutions to the quadratic equation are:

x = 2 - 2 i, x = 2 + 2 i

p^{2} - 11 p + 28 = 0

∣ 6 - 4 x ∣ \leq 1

2 (\frac{1}{5})^{2}

(- \frac{5}{4})^{3}

\frac{1}{2} ln (4 t^{4}) - ln (2)

What are the solutions to the equation -x^2+4x=6 ?
The solutions to the equation -x^2+4x=6 are x=2-sqrt(2)i,x=2+sqrt(2)i
Find the zeros of -x^2+4x=6
The zeros of -x^2+4x=6 are x=2-sqrt(2)i,x=2+sqrt(2)i