What are the solutions to the equation 9x^2+4x-5=0 ?

The solutions to the equation 9x^2+4x-5=0 are x= 5/9 ,x=-1

Find the zeros of 9x^2+4x-5=0

The zeros of 9x^2+4x-5=0 are x= 5/9 ,x=-1

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9 x^{2} + 4 x - 5 = 0

x = \frac{5}{9}, x = - 1

Decimal Notation

x = 0.55555 \dots, x = - 1

Solution steps

9 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

4^{2} - 4 \cdot 9 (- 5) = 14

x_{1, 2} = \frac{- 4 \pm 14}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 4 + 14}{2 \cdot 9}, x_{2} = \frac{- 4 - 14}{2 \cdot 9}

x = \frac{- 4 + 14}{2 \cdot 9} : \frac{5}{9}

x = \frac{- 4 - 14}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{9}, x = - 1

4 x^{2} + 16 x - 20 = 0

15 w^{2} - 14 w - 8 = 0

2 m^{2} + 3 m + 2 = 0

λ^{2} - 3 λ + 2 (1) = 0

y^{2} + 2 = 6

What are the solutions to the equation 9x^2+4x-5=0 ?
The solutions to the equation 9x^2+4x-5=0 are x= 5/9 ,x=-1
Find the zeros of 9x^2+4x-5=0
The zeros of 9x^2+4x-5=0 are x= 5/9 ,x=-1