What are the solutions to the equation solvefor x,t+x^2=p ?

The solutions to the equation solvefor x,t+x^2=p are x=sqrt(p-t),x=-sqrt(p-t)

Find the zeros of solvefor x,t+x^2=p

The zeros of solvefor x,t+x^2=p are x=sqrt(p-t),x=-sqrt(p-t)

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solve for

x, t + x^{2} = p

x = p - t, x = - p - t

Solution steps

t + x^{2} = p

Move

t

to the right side

x^{2} = p - t

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = p - t, x = - p - t

(5 x + 11) (3 x - 7) = 0

2 t^{2} - 10 t - 5 = 0

3 x^{2} + 7 x = - 4

5 x^{2} = - 15 x

5 x^{2} = - 13 x

What are the solutions to the equation solvefor x,t+x^2=p ?
The solutions to the equation solvefor x,t+x^2=p are x=sqrt(p-t),x=-sqrt(p-t)
Find the zeros of solvefor x,t+x^2=p
The zeros of solvefor x,t+x^2=p are x=sqrt(p-t),x=-sqrt(p-t)