What are the solutions to the equation x^2+6x-19=23 ?

The solutions to the equation x^2+6x-19=23 are x=-3+sqrt(51),x=-3-sqrt(51)

Find the zeros of x^2+6x-19=23

The zeros of x^2+6x-19=23 are x=-3+sqrt(51),x=-3-sqrt(51)

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x^{2} + 6 x - 19 = 23

x = - 3 + 51, x = - 3 - 51

Decimal Notation

x = 4.14142 \dots, x = - 10.14142 \dots

Solution steps

x^{2} + 6 x - 19 = 23

Move

23

to the left side

x^{2} + 6 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 42) = 251

x_{1, 2} = \frac{- 6 \pm 2 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 51}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 51}{2 \cdot 1}

x = \frac{- 6 + 2 51}{2 \cdot 1} : - 3 + 51

x = \frac{- 6 - 2 51}{2 \cdot 1} : - 3 - 51

The solutions to the quadratic equation are:

x = - 3 + 51, x = - 3 - 51

x^{2} - \frac{8}{3} x + \frac{16}{9} = 0

x^{2} + 2 x - 70 = 0

3 p^{2} - 3 p - 6 = - 2

64 x^{2} - 212 x + 49 = 0

x^{2} = 4 x - 29

What are the solutions to the equation x^2+6x-19=23 ?
The solutions to the equation x^2+6x-19=23 are x=-3+sqrt(51),x=-3-sqrt(51)
Find the zeros of x^2+6x-19=23
The zeros of x^2+6x-19=23 are x=-3+sqrt(51),x=-3-sqrt(51)