What are the solutions to the equation 2=(1/2)(x-4)^2 ?

The solutions to the equation 2=(1/2)(x-4)^2 are x=6,x=2

Find the zeros of 2=(1/2)(x-4)^2

The zeros of 2=(1/2)(x-4)^2 are x=6,x=2

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2 = (\frac{1}{2}) (x - 4)^{2}

x = 6, x = 2

Solution steps

2 = (\frac{1}{2}) (x - 4)^{2}

Switch sides

(\frac{1}{2}) (x - 4)^{2} = 2

Multiply both sides by

2

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

(x + 1) (x - 3) = 3

x, x^{2} - y^{2} = z

2 X^{2} + 12 X + 16 = 0

x^{2} + 5 x + 8 = 4

55 w = - 20 w^{(2)} - 30

What are the solutions to the equation 2=(1/2)(x-4)^2 ?
The solutions to the equation 2=(1/2)(x-4)^2 are x=6,x=2
Find the zeros of 2=(1/2)(x-4)^2
The zeros of 2=(1/2)(x-4)^2 are x=6,x=2