What are the solutions to the equation 7x^2+10=2x ?

The solutions to the equation 7x^2+10=2x are x= 1/7+i(sqrt(69))/7 ,x= 1/7-i(sqrt(69))/7

Find the zeros of 7x^2+10=2x

The zeros of 7x^2+10=2x are x= 1/7+i(sqrt(69))/7 ,x= 1/7-i(sqrt(69))/7

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7 x^{2} + 10 = 2 x

x = \frac{1}{7} + i \frac{69}{7}, x = \frac{1}{7} - i \frac{69}{7}

Solution steps

7 x^{2} + 10 = 2 x

Move

2 x

to the left side

7 x^{2} + 10 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 \cdot 10}{2 \cdot 7}

Simplify

(- 2)^{2} - 4 \cdot 7 \cdot 10 : 269 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 69 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 69 i}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 69 i}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 69 i}{2 \cdot 7} : \frac{1}{7} + i \frac{69}{7}

x = \frac{- ( - 2 ) - 2 69 i}{2 \cdot 7} : \frac{1}{7} - i \frac{69}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{69}{7}, x = \frac{1}{7} - i \frac{69}{7}

3 x^{2} + 18 = - 9 x

x^{2} - 300 x + 16100 = 0

x, x^{2} + y^{2} - 2 x - 8 y + 20 = 0

- 3 x^{2} = - 54

x^{2} - 4 = 60

What are the solutions to the equation 7x^2+10=2x ?
The solutions to the equation 7x^2+10=2x are x= 1/7+i(sqrt(69))/7 ,x= 1/7-i(sqrt(69))/7
Find the zeros of 7x^2+10=2x
The zeros of 7x^2+10=2x are x= 1/7+i(sqrt(69))/7 ,x= 1/7-i(sqrt(69))/7