What are the solutions to the equation 4x^2-8x=-4 ?

The solutions to the equation 4x^2-8x=-4 are x=1

Find the zeros of 4x^2-8x=-4

The zeros of 4x^2-8x=-4 are x=1

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4 x^{2} - 8 x = - 4

x = 1

Solution steps

4 x^{2} - 8 x = - 4

Move

4

to the left side

4 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 8 )}{2 \cdot 4}

\frac{- ( - 8 )}{2 \cdot 4} = 1

x = 1

The solution to the quadratic equation is:

x = 1

2 (- \frac{1}{5})

\frac{10 i}{4 + 2 i}

lo g_{b} (\frac{x ^{2} y}{z ^{8}})

450

\frac{4}{5} x - \frac{1}{2} = x

What are the solutions to the equation 4x^2-8x=-4 ?
The solutions to the equation 4x^2-8x=-4 are x=1
Find the zeros of 4x^2-8x=-4
The zeros of 4x^2-8x=-4 are x=1