What are the solutions to the equation 3(x-6)^2-6=210 ?

The solutions to the equation 3(x-6)^2-6=210 are x=6sqrt(2)+6,x=-6sqrt(2)+6

Find the zeros of 3(x-6)^2-6=210

The zeros of 3(x-6)^2-6=210 are x=6sqrt(2)+6,x=-6sqrt(2)+6

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3 (x - 6)^{2} - 6 = 210

x = 62 + 6, x = - 62 + 6

Decimal Notation

x = 14.48528 \dots, x = - 2.48528 \dots

Solution steps

3 (x - 6)^{2} - 6 = 210

Move

6

to the right side

3 (x - 6)^{2} = 216

Divide both sides by

3

(x - 6)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = 72 : x = 62 + 6

Solve

x - 6 = - 72 : x = - 62 + 6

The solutions to the quadratic equation are:

x = 62 + 6, x = - 62 + 6

(x^{2} + 2 x^{2} + 3) = (x + 3 x + x^{2} - 5)

y, x^{2} + y^{2} = a^{2}

2 x^{2} - 144 = - 2 x

x^{2} + 1.4 x + 1 = 0

10000 x^{2} - 64 = 0

What are the solutions to the equation 3(x-6)^2-6=210 ?
The solutions to the equation 3(x-6)^2-6=210 are x=6sqrt(2)+6,x=-6sqrt(2)+6
Find the zeros of 3(x-6)^2-6=210
The zeros of 3(x-6)^2-6=210 are x=6sqrt(2)+6,x=-6sqrt(2)+6