What are the solutions to the equation (x-5)^2+10(x-5)+25=0 ?

The solutions to the equation (x-5)^2+10(x-5)+25=0 are x=0

Find the zeros of (x-5)^2+10(x-5)+25=0

The zeros of (x-5)^2+10(x-5)+25=0 are x=0

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(x - 5)^{2} + 10 (x - 5) + 25 = 0

x = 0

Solution steps

(x - 5)^{2} + 10 (x - 5) + 25 = 0

Expand

(x - 5)^{2} + 10 (x - 5) + 25 : x^{2}

x^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot 0 = 0

x_{1, 2} = \frac{- 0 \pm 0}{2 \cdot 1}

x = \frac{- 0}{2 \cdot 1}

\frac{- 0}{2 \cdot 1} = 0

x = 0

The solution to the quadratic equation is:

x = 0

12 (x - 2)^{2} = 0

x^{2} + (\frac{1}{6})^{2} - 1 = 0

x^{2} + \frac{8}{6} x = 0

4 x^{2} = 6

5 x^{2} - 40 x + 80 = 0

What are the solutions to the equation (x-5)^2+10(x-5)+25=0 ?
The solutions to the equation (x-5)^2+10(x-5)+25=0 are x=0
Find the zeros of (x-5)^2+10(x-5)+25=0
The zeros of (x-5)^2+10(x-5)+25=0 are x=0