What are the solutions to the equation -2x^2+3x+10=0 ?

The solutions to the equation -2x^2+3x+10=0 are x=-(-3+sqrt(89))/4 ,x=(3+sqrt(89))/4

Find the zeros of -2x^2+3x+10=0

The zeros of -2x^2+3x+10=0 are x=-(-3+sqrt(89))/4 ,x=(3+sqrt(89))/4

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- 2 x^{2} + 3 x + 10 = 0

x = - \frac{- 3 + 89}{4}, x = \frac{3 + 89}{4}

Decimal Notation

x = - 1.60849 \dots, x = 3.10849 \dots

Solution steps

- 2 x^{2} + 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 10 = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 ( - 2 )}, x_{2} = \frac{- 3 - 89}{2 ( - 2 )}

x = \frac{- 3 + 89}{2 ( - 2 )} : - \frac{- 3 + 89}{4}

x = \frac{- 3 - 89}{2 ( - 2 )} : \frac{3 + 89}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 89}{4}, x = \frac{3 + 89}{4}

- x = 30 - 20 x^{2}

2^{2} + b^{2} = 4^{2}

2 x^{2} + x - 4 = - 6 x - 7

(x + 5)^{2} + 3 x = (x + 3) (2 x - 1)

8 x = 3 x^{2} + 5

What are the solutions to the equation -2x^2+3x+10=0 ?
The solutions to the equation -2x^2+3x+10=0 are x=-(-3+sqrt(89))/4 ,x=(3+sqrt(89))/4
Find the zeros of -2x^2+3x+10=0
The zeros of -2x^2+3x+10=0 are x=-(-3+sqrt(89))/4 ,x=(3+sqrt(89))/4