What are the solutions to the equation (x+2)^2=a ?

The solutions to the equation (x+2)^2=a are x=sqrt(a)-2,x=-sqrt(a)-2

Find the zeros of (x+2)^2=a

The zeros of (x+2)^2=a are x=sqrt(a)-2,x=-sqrt(a)-2

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(x + 2)^{2} = a

x = a - 2, x = - a - 2

Solution steps

(x + 2)^{2} = a

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = a : x = a - 2

Solve

x + 2 = - a : x = - a - 2

The solutions to the quadratic equation are:

x = a - 2, x = - a - 2

- x^{2} + 6 x = x

2 x^{2} - 10 = - x

3 (2 b + 3)^{2} = 36

(x - a)^{2} = b^{2}

- 3 y^{2} + 5 y - 15 = - 4 y^{2}

What are the solutions to the equation (x+2)^2=a ?
The solutions to the equation (x+2)^2=a are x=sqrt(a)-2,x=-sqrt(a)-2
Find the zeros of (x+2)^2=a
The zeros of (x+2)^2=a are x=sqrt(a)-2,x=-sqrt(a)-2