What are the solutions to the equation (-x+6)^2-12=0 ?

The solutions to the equation (-x+6)^2-12=0 are x=6-2sqrt(3),x=2sqrt(3)+6

Find the zeros of (-x+6)^2-12=0

The zeros of (-x+6)^2-12=0 are x=6-2sqrt(3),x=2sqrt(3)+6

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(- x + 6)^{2} - 12 = 0

x = 6 - 23, x = 23 + 6

Decimal Notation

x = 2.53589 \dots, x = 9.46410 \dots

Solution steps

(- x + 6)^{2} - 12 = 0

Move

12

to the right side

(- x + 6)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- x + 6 = 12 : x = 6 - 23

Solve

- x + 6 = - 12 : x = 23 + 6

The solutions to the quadratic equation are:

x = 6 - 23, x = 23 + 6

- x^{2} - 70 x + 2139 = 0

25 y^{2} - 9 y - 180 = 0

5 x^{2} - 31 x - 72 = 0

80 + 40 x - 4.9 x^{2} = 0

x^{2} + 16 = 12 x

What are the solutions to the equation (-x+6)^2-12=0 ?
The solutions to the equation (-x+6)^2-12=0 are x=6-2sqrt(3),x=2sqrt(3)+6
Find the zeros of (-x+6)^2-12=0
The zeros of (-x+6)^2-12=0 are x=6-2sqrt(3),x=2sqrt(3)+6