What are the solutions to the equation 9x^2+6x+2=0 ?

The solutions to the equation 9x^2+6x+2=0 are x=-1/3+i 1/3 ,x=-1/3-i 1/3

Find the zeros of 9x^2+6x+2=0

The zeros of 9x^2+6x+2=0 are x=-1/3+i 1/3 ,x=-1/3-i 1/3

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9 x^{2} + 6 x + 2 = 0

x = - \frac{1}{3} + i \frac{1}{3}, x = - \frac{1}{3} - i \frac{1}{3}

Solution steps

9 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 2 : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 i}{2 \cdot 9}

x = \frac{- 6 + 6 i}{2 \cdot 9} : - \frac{1}{3} + i \frac{1}{3}

x = \frac{- 6 - 6 i}{2 \cdot 9} : - \frac{1}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{1}{3}, x = - \frac{1}{3} - i \frac{1}{3}

29 x - 11 = 15 x + 45

x^{2} + 3 x y + 3 x^{3} + y

x + 5 \geq 10

\frac{e ^{2 t}}{e ^{t}}

1 - \frac{1}{75} x^{2} = 0

What are the solutions to the equation 9x^2+6x+2=0 ?
The solutions to the equation 9x^2+6x+2=0 are x=-1/3+i 1/3 ,x=-1/3-i 1/3
Find the zeros of 9x^2+6x+2=0
The zeros of 9x^2+6x+2=0 are x=-1/3+i 1/3 ,x=-1/3-i 1/3