What are the solutions to the equation s^2+2s+26=0 ?

The solutions to the equation s^2+2s+26=0 are s=-1+5i,s=-1-5i

Find the zeros of s^2+2s+26=0

The zeros of s^2+2s+26=0 are s=-1+5i,s=-1-5i

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s^{2} + 2 s + 26 = 0

s = - 1 + 5 i, s = - 1 - 5 i

Solution steps

s^{2} + 2 s + 26 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 26 : 10 i

s_{1, 2} = \frac{- 2 \pm 10 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 10 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 10 i}{2 \cdot 1}

s = \frac{- 2 + 10 i}{2 \cdot 1} : - 1 + 5 i

s = \frac{- 2 - 10 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

s = - 1 + 5 i, s = - 1 - 5 i

\frac{14 \cdot x ^{2}}{2} - 8.69 \cdot 4 \cdot (40.5 - x) = 0

x^{2} - 46 x + 630 = 0

4 x^{2} + 15 x - 25 = 0

x, 3 x^{2} + 3 y^{2} - 3 x + 7 y + 15 = 0

2 x^{2} - 2 x

What are the solutions to the equation s^2+2s+26=0 ?
The solutions to the equation s^2+2s+26=0 are s=-1+5i,s=-1-5i
Find the zeros of s^2+2s+26=0
The zeros of s^2+2s+26=0 are s=-1+5i,s=-1-5i