What are the solutions to the equation x^2-13x+4=17 ?

The solutions to the equation x^2-13x+4=17 are x=(13+sqrt(221))/2 ,x=(13-sqrt(221))/2

Find the zeros of x^2-13x+4=17

The zeros of x^2-13x+4=17 are x=(13+sqrt(221))/2 ,x=(13-sqrt(221))/2

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x^{2} - 13 x + 4 = 17

x = \frac{13 + 221}{2}, x = \frac{13 - 221}{2}

Decimal Notation

x = 13.93303 \dots, x = - 0.93303 \dots

Solution steps

x^{2} - 13 x + 4 = 17

Move

17

to the left side

x^{2} - 13 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 13) = 221

x_{1, 2} = \frac{- ( - 13 ) \pm 221}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 221}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 221}{2 \cdot 1}

x = \frac{- ( - 13 ) + 221}{2 \cdot 1} : \frac{13 + 221}{2}

x = \frac{- ( - 13 ) - 221}{2 \cdot 1} : \frac{13 - 221}{2}

The solutions to the quadratic equation are:

x = \frac{13 + 221}{2}, x = \frac{13 - 221}{2}

x^{2} = - 2, x^{1} = 0

4.5 x^{2} + 2 = 32.7

(5 x + 3) (x - 2) = 8 (x - 2)

10 x^{2} - 25 = x^{2}

- 4 x^{2} + 12 x - 8 = 0

What are the solutions to the equation x^2-13x+4=17 ?
The solutions to the equation x^2-13x+4=17 are x=(13+sqrt(221))/2 ,x=(13-sqrt(221))/2
Find the zeros of x^2-13x+4=17
The zeros of x^2-13x+4=17 are x=(13+sqrt(221))/2 ,x=(13-sqrt(221))/2