What are the solutions to the equation x^2+10x+24=15 ?

The solutions to the equation x^2+10x+24=15 are x=-1,x=-9

Find the zeros of x^2+10x+24=15

The zeros of x^2+10x+24=15 are x=-1,x=-9

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x^{2} + 10 x + 24 = 15

x = - 1, x = - 9

Solution steps

x^{2} + 10 x + 24 = 15

Move

15

to the left side

x^{2} + 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 8}{2 \cdot 1}, x_{2} = \frac{- 10 - 8}{2 \cdot 1}

x = \frac{- 10 + 8}{2 \cdot 1} : - 1

x = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 1, x = - 9

(x + 9)^{2} = 49

\frac{( x + 2 ) ^{2}}{5} - \frac{x ^{2} - 9}{4} = \frac{( x - 3 ) ^{2}}{2} + \frac{1}{5}

(2 x)^{2} + (2 x + 3)^{2} = 369

4 (x - 2)^{2} + 1 = 21

x^{2} - 2 (m - 2) x + (m^{2} - 2 m - 3) = 0

What are the solutions to the equation x^2+10x+24=15 ?
The solutions to the equation x^2+10x+24=15 are x=-1,x=-9
Find the zeros of x^2+10x+24=15
The zeros of x^2+10x+24=15 are x=-1,x=-9