What are the solutions to the equation 5x^2-10x+13=0 ?

The solutions to the equation 5x^2-10x+13=0 are x=1+i(2sqrt(10))/5 ,x=1-i(2sqrt(10))/5

Find the zeros of 5x^2-10x+13=0

The zeros of 5x^2-10x+13=0 are x=1+i(2sqrt(10))/5 ,x=1-i(2sqrt(10))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 10 x + 13 = 0

x = 1 + i \frac{2 10}{5}, x = 1 - i \frac{2 10}{5}

Solution steps

5 x^{2} - 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 13}{2 \cdot 5}

Simplify

(- 10)^{2} - 4 \cdot 5 \cdot 13 : 410 i

x_{1, 2} = \frac{- ( - 10 ) \pm 4 10 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 10 i}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 4 10 i}{2 \cdot 5}

x = \frac{- ( - 10 ) + 4 10 i}{2 \cdot 5} : 1 + i \frac{2 10}{5}

x = \frac{- ( - 10 ) - 4 10 i}{2 \cdot 5} : 1 - i \frac{2 10}{5}

The solutions to the quadratic equation are:

x = 1 + i \frac{2 10}{5}, x = 1 - i \frac{2 10}{5}

lo g_{7} (3) x^{2} - lo g_{7} (3) = 4

(x - 2) (x + 1) = 6

1 2^{2} + x^{2} = 1 6^{2}

x, x^{2} - y^{2} = x - y

(8 x 3 + 125) = (2 x + a) (b x 2 - 10 x + c)

What are the solutions to the equation 5x^2-10x+13=0 ?
The solutions to the equation 5x^2-10x+13=0 are x=1+i(2sqrt(10))/5 ,x=1-i(2sqrt(10))/5
Find the zeros of 5x^2-10x+13=0
The zeros of 5x^2-10x+13=0 are x=1+i(2sqrt(10))/5 ,x=1-i(2sqrt(10))/5