What are the solutions to the equation 7x^2-12x+3=0 ?

The solutions to the equation 7x^2-12x+3=0 are x=(6+sqrt(15))/7 ,x=(6-sqrt(15))/7

Find the zeros of 7x^2-12x+3=0

The zeros of 7x^2-12x+3=0 are x=(6+sqrt(15))/7 ,x=(6-sqrt(15))/7

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7 x^{2} - 12 x + 3 = 0

x = \frac{6 + 15}{7}, x = \frac{6 - 15}{7}

Decimal Notation

x = 1.41042 \dots, x = 0.30385 \dots

Solution steps

7 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

(- 12)^{2} - 4 \cdot 7 \cdot 3 = 215

x_{1, 2} = \frac{- ( - 12 ) \pm 2 15}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 15}{2 \cdot 7}, x_{2} = \frac{- ( - 12 ) - 2 15}{2 \cdot 7}

x = \frac{- ( - 12 ) + 2 15}{2 \cdot 7} : \frac{6 + 15}{7}

x = \frac{- ( - 12 ) - 2 15}{2 \cdot 7} : \frac{6 - 15}{7}

The solutions to the quadratic equation are:

x = \frac{6 + 15}{7}, x = \frac{6 - 15}{7}

3 x^{2} = 11 x - 6

x, x^{2} + y^{2} + 2 x - 6 y + 10 = 0

- 6 x^{2} - 7 x - 10 = - 6

3 x^{2} - 6 = 34 - 2 x^{2}

2 x^{2} + 9 x + 10 = 0

What are the solutions to the equation 7x^2-12x+3=0 ?
The solutions to the equation 7x^2-12x+3=0 are x=(6+sqrt(15))/7 ,x=(6-sqrt(15))/7
Find the zeros of 7x^2-12x+3=0
The zeros of 7x^2-12x+3=0 are x=(6+sqrt(15))/7 ,x=(6-sqrt(15))/7