What are the solutions to the equation 6x^2-18x-5=0 ?

The solutions to the equation 6x^2-18x-5=0 are x=(9+sqrt(111))/6 ,x=(9-sqrt(111))/6

Find the zeros of 6x^2-18x-5=0

The zeros of 6x^2-18x-5=0 are x=(9+sqrt(111))/6 ,x=(9-sqrt(111))/6

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6 x^{2} - 18 x - 5 = 0

x = \frac{9 + 111}{6}, x = \frac{9 - 111}{6}

Decimal Notation

x = 3.25594 \dots, x = - 0.25594 \dots

Solution steps

6 x^{2} - 18 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 18)^{2} - 4 \cdot 6 (- 5) = 2111

x_{1, 2} = \frac{- ( - 18 ) \pm 2 111}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 111}{2 \cdot 6}, x_{2} = \frac{- ( - 18 ) - 2 111}{2 \cdot 6}

x = \frac{- ( - 18 ) + 2 111}{2 \cdot 6} : \frac{9 + 111}{6}

x = \frac{- ( - 18 ) - 2 111}{2 \cdot 6} : \frac{9 - 111}{6}

The solutions to the quadratic equation are:

x = \frac{9 + 111}{6}, x = \frac{9 - 111}{6}

2 x^{2} - 1 x = 3

\frac{1}{8} x^{2} + x + \frac{3}{4} = 0

x (x - 14) + 48 = 0

x, 2 x^{2} + 2 y^{2} - 12 y + 35 = 0

x^{2} - 4 x - 4 + 8 = 0

What are the solutions to the equation 6x^2-18x-5=0 ?
The solutions to the equation 6x^2-18x-5=0 are x=(9+sqrt(111))/6 ,x=(9-sqrt(111))/6
Find the zeros of 6x^2-18x-5=0
The zeros of 6x^2-18x-5=0 are x=(9+sqrt(111))/6 ,x=(9-sqrt(111))/6