What are the solutions to the equation 2x^2+24x-6=0 ?

The solutions to the equation 2x^2+24x-6=0 are x=-6+sqrt(39),x=-6-sqrt(39)

Find the zeros of 2x^2+24x-6=0

The zeros of 2x^2+24x-6=0 are x=-6+sqrt(39),x=-6-sqrt(39)

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2 x^{2} + 24 x - 6 = 0

x = - 6 + 39, x = - 6 - 39

Decimal Notation

x = 0.24499 \dots, x = - 12.24499 \dots

Solution steps

2 x^{2} + 24 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

2 4^{2} - 4 \cdot 2 (- 6) = 439

x_{1, 2} = \frac{- 24 \pm 4 39}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 24 + 4 39}{2 \cdot 2}, x_{2} = \frac{- 24 - 4 39}{2 \cdot 2}

x = \frac{- 24 + 4 39}{2 \cdot 2} : - 6 + 39

x = \frac{- 24 - 4 39}{2 \cdot 2} : - 6 - 39

The solutions to the quadratic equation are:

x = - 6 + 39, x = - 6 - 39

1.25 \cdot 1 0^{- 9} x^{2} + 20 \cdot 1 0^{- 6} x + 0.125 = 0

52 + 2 q = 100 - q^{2}

9 x^{2} + 27 x + 14 = 0

1000 = \frac{1}{2} \cdot 0.47 \cdot \frac{π \cdot D ^{2}}{4} \cdot 1.2256 \cdot 5^{3}

5 x^{2} + 34 x - 7 = 0

What are the solutions to the equation 2x^2+24x-6=0 ?
The solutions to the equation 2x^2+24x-6=0 are x=-6+sqrt(39),x=-6-sqrt(39)
Find the zeros of 2x^2+24x-6=0
The zeros of 2x^2+24x-6=0 are x=-6+sqrt(39),x=-6-sqrt(39)