What are the solutions to the equation completesquare 1/4 x^2+8x-1 ?

The solutions to the equation completesquare 1/4 x^2+8x-1 are 1/4 (x+16)^2-65

Find the zeros of completesquare 1/4 x^2+8x-1

The zeros of completesquare 1/4 x^2+8x-1 are 1/4 (x+16)^2-65

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complete the square

\frac{1}{4} x^{2} + 8 x - 1

\frac{1}{4} (x + 16)^{2} - 65

Solution steps

\frac{1}{4} x^{2} + 8 x - 1

Write in the standard form

a x^{2} + b x + c

\frac{x ^{2}}{4} + 8 x - 1

Write

\frac{x ^{2}}{4} + 8 x - 1

in the form:

x^{2} + 2 a x + a^{2}

Factor out

\frac{1}{4}

\frac{1}{4} (x^{2} + 32 x - 4)

2 a = 32 : a = 16

Add and subtract

1 6^{2}

\frac{1}{4} (x^{2} + 32 x - 4 + 1 6^{2} - 1 6^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 32 x + 1 6^{2} = (x + 16)^{2}

\frac{1}{4} ((x + 16)^{2} - 4 - 1 6^{2})

Simplify

\frac{1}{4} (x + 16)^{2} - 65

a^{2} = 0

x^{2} = 0.7

(x + 5) (x - 4) = x + 16

16 x^{2} = 0

x, (x - 3)^{2} + y^{2} + x^{2} + 9 = 0

What are the solutions to the equation completesquare 1/4 x^2+8x-1 ?
The solutions to the equation completesquare 1/4 x^2+8x-1 are 1/4 (x+16)^2-65
Find the zeros of completesquare 1/4 x^2+8x-1
The zeros of completesquare 1/4 x^2+8x-1 are 1/4 (x+16)^2-65