What are the solutions to the equation 2x^2+7/3 =2+5/9 ?

The solutions to the equation 2x^2+7/3 =2+5/9 are x= 1/3 ,x=-1/3

Find the zeros of 2x^2+7/3 =2+5/9

The zeros of 2x^2+7/3 =2+5/9 are x= 1/3 ,x=-1/3

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2 x^{2} + \frac{7}{3} = 2 + \frac{5}{9}

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.33333 \dots, x = - 0.33333 \dots

Solution steps

2 x^{2} + \frac{7}{3} = 2 + \frac{5}{9}

Move

\frac{7}{3}

to the right side

2 x^{2} = 2 + \frac{5}{9} - \frac{7}{3}

Simplify

2 + \frac{5}{9} - \frac{7}{3} : \frac{2}{9}

2 x^{2} = \frac{2}{9}

Divide both sides by

2

x^{2} = \frac{1}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{9}, x = - \frac{1}{9}

\frac{1}{9} = \frac{1}{3}

- \frac{1}{9} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

4 - 3 x = - x^{2} + 3 x

8 x^{2} - 26 x + 15 = 0

2 x^{2} - 6 x + 1

y^{2} + 4 y - 60 = 0

(x + 8)^{2} + (x - 10)^{2} = - 156

What are the solutions to the equation 2x^2+7/3 =2+5/9 ?
The solutions to the equation 2x^2+7/3 =2+5/9 are x= 1/3 ,x=-1/3
Find the zeros of 2x^2+7/3 =2+5/9
The zeros of 2x^2+7/3 =2+5/9 are x= 1/3 ,x=-1/3